hint 1 hint 2 hint 3 hint 4 hint 5\nbelow are iq scores from 30 randomly selected adults.\n{ 83, 85, 88, 89…

Explanation:

Step1: Calculate the mean

The mean $\bar{x}=\frac{\sum_{i = 1}^{n}x_{i}}{n}$, where $n = 30$ and $x_{i}$ are the data - points. $\sum_{i=1}^{30}x_{i}=83 + 85+88+\cdots+130=3126$, so $\bar{x}=\frac{3126}{30}=104.2$.

Step2: Calculate the median

Since $n = 30$ (an even number), the median is the average of the $\frac{n}{2}$ - th and $(\frac{n}{2}+1)$ - th ordered data - points. The 15th and 16th ordered data - points are 102 and 103, so the median $=\frac{102 + 103}{2}=102.5$.

Step3: Determine the mode

The mode is the data - point that appears most frequently. In the data set, 122 appears 3 times, more frequently than any other number, so the mode is 122.

Step4: Calculate the mid - range

The mid - range is calculated as $\frac{\text{Minimum value}+\text{Maximum value}}{2}$. The minimum value is 83 and the maximum value is 130, so the mid - range $=\frac{83 + 130}{2}=106.5$.

Step5: Analyze the shape of the distribution

The mean ($\bar{x}=104.2$) is greater than the median ($102.5$). In a distribution, when the mean is greater than the median, the distribution is likely to be skewed to the right.

Answer:

Part 1: 104.2 Part 2: 102.5 Part 3: 122 Part 4: 106.5 Part 5: The distribution will probably be skewed to the right.