histograms practice\n5. the histogram below shows the ages of people attending the showing of a new…

histograms practice\n5. the histogram below shows the ages of people attending the showing of a new movie.\na) how many people attended the movie?\nb) what would you estimate the median age of moviegoers to be?\nc) what kind of movie might this be?\ngiven the histogram below, answer the questions:\na) how would you describe the shape of this distribution?\nb) what would you estimate the mean and median to be?\nmiles per gallon\nwww.analyzemath.com
Answer
Explanation:
Step1: Find total number of attendees
Sum up the frequencies in the age - based histogram. $5 + 60+55 + 20+10+15+5+2+1=173$
Step2: Estimate the median age
There are $n = 173$ data points. The median is the $\left(\frac{n + 1}{2}\right)$-th value. $\frac{173+1}{2}=87$-th value. Counting the frequencies from the left, the first bar ($0 - 5$) has $5$ people, the second bar ($5 - 10$) has $60$ people, and the third bar ($10 - 15$) has $55$ people. The cumulative frequency up to the ($5 - 10$) age - group is $5+60 = 65$, and up to the ($10 - 15$) age - group is $5+60 + 55=120$. So the median lies in the ($10 - 15$) age - group. A reasonable estimate could be $12$.
Step3: Guess the movie type
The age distribution is skewed towards younger ages. A possible type of movie could be a children's or a teen - targeted movie.
Step4: Describe the shape of the MPG histogram
The shape of the miles - per - gallon histogram is approximately symmetric. The bars on either side of the center are roughly mirror - images of each other.
Step5: Estimate mean and median of MPG histogram
Since it is symmetric, the mean and median are approximately equal. The center of the distribution seems to be around $17.5$ (mid - point of the tallest bar's interval). So both mean and median can be estimated as $17.5$.
Answer:
a) 173 b) 12 c) Children's or teen - targeted movie a) Symmetric b) Mean: 17.5, Median: 17.5