homework 1\nscore: 7.8/20 answered: 10/20\nquestion 11\nbased on the frequency distribution above, find the…

Answer:

22

Explanation:

Step1: Calculate cumulative frequency

Cumulative frequency is the sum of frequencies of all classes before and including the class of interest. For the class (31 - 34), we sum the frequencies of (15 - 18) ((3)), (19 - 22) ((4)), (23 - 26) ((9)), (27 - 30) ((6)) and (31 - 34) ((4)). [3 + 4+9 + 6+4]

Step2: Perform addition

[3+4 = 7] [7+9 = 16] [16+6 = 22] [22+4 = 26] (Wait, no. Wait, cumulative frequency for the class (31 - 34) is sum of frequencies of (15 - 18), (19 - 22), (23 - 26), (27 - 30) and (31 - 34) itself. (3+4 + 9+6+4=26). But wait, no. Wait, cumulative frequency up to and including a class. Another approach: [3+4=7] (cumulative up to (19 - 22)) [7 + 9=16] (cumulative up to (23 - 26)) [16+6 = 22] (cumulative up to (27 - 30)) [22+4=26] (cumulative up to (31 - 34))

So the cumulative frequency for the class with lower - class limit (31) (i.e., the class (31 - 34)) is (26) (no rounding needed as it's an integer. But if we assume a mis - understanding and if the problem was for relative cumulative frequency (but the question says cumulative frequency). Wait, re - check: cumulative frequency is just the sum. (3+4 + 9+6+4=26)