homework: section 4.2\nscore: 14/15 answered: 14/15\nquestion 15\nx p(x)\n0 0.3\n1 0.25\n2 0.1\n3 0.35\na…

homework: section 4.2\nscore: 14/15 answered: 14/15\nquestion 15\nx p(x)\n0 0.3\n1 0.25\n2 0.1\n3 0.35\na. find the expected value of the probability distribution. round to two decimal places.\nb. find the standard deviation of the probability distribution. round to two decimal places.
Answer
Explanation:
Step1: Recall expected - value formula
The formula for the expected value $E(X)$ of a discrete probability distribution is $E(X)=\sum_{i}x_{i}P(x_{i})$. [ \begin{align*} E(X)&=(0\times0.3)+(1\times0.25)+(2\times0.1)+(3\times0.35)\ &=0 + 0.25+0.2 + 1.05\ &=1.50 \end{align*} ]
Step2: Recall variance formula
The formula for the variance $\text{Var}(X)=\sum_{i}(x_{i}-E(X))^{2}P(x_{i})$. First, calculate $(x_{i}-E(X))^{2}P(x_{i})$ for each $x_{i}$:
- For $x = 0$: $(0 - 1.5)^{2}\times0.3=( - 1.5)^{2}\times0.3 = 2.25\times0.3=0.675$
- For $x = 1$: $(1 - 1.5)^{2}\times0.25=( - 0.5)^{2}\times0.25 = 0.25\times0.25 = 0.0625$
- For $x = 2$: $(2 - 1.5)^{2}\times0.1=(0.5)^{2}\times0.1 = 0.25\times0.1=0.025$
- For $x = 3$: $(3 - 1.5)^{2}\times0.35=(1.5)^{2}\times0.35 = 2.25\times0.35 = 0.7875$ Then, $\text{Var}(X)=0.675 + 0.0625+0.025 + 0.7875=1.55$
Step3: Calculate standard - deviation
The standard deviation $\sigma=\sqrt{\text{Var}(X)}$. $\sigma=\sqrt{1.55}\approx1.24$
Answer:
a. $1.50$ b. $1.24$