homework: section 4.2\nscore: 14/15 answered: 14/15\nquestion 15\nx p(x)\n0 0.3\n1 0.25\n2 0.1\n3 0.35\na…

homework: section 4.2\nscore: 14/15 answered: 14/15\nquestion 15\nx p(x)\n0 0.3\n1 0.25\n2 0.1\n3 0.35\na. find the expected value of the probability distribution. round to two decimal places.\nb. find the standard deviation of the probability distribution. round to two decimal places.

homework: section 4.2\nscore: 14/15 answered: 14/15\nquestion 15\nx p(x)\n0 0.3\n1 0.25\n2 0.1\n3 0.35\na. find the expected value of the probability distribution. round to two decimal places.\nb. find the standard deviation of the probability distribution. round to two decimal places.

Answer

Explanation:

Step1: Recall expected - value formula

The formula for the expected value $E(X)$ of a discrete probability distribution is $E(X)=\sum_{i}x_{i}P(x_{i})$. [ \begin{align*} E(X)&=(0\times0.3)+(1\times0.25)+(2\times0.1)+(3\times0.35)\ &=0 + 0.25+0.2 + 1.05\ &=1.50 \end{align*} ]

Step2: Recall variance formula

The formula for the variance $\text{Var}(X)=\sum_{i}(x_{i}-E(X))^{2}P(x_{i})$. First, calculate $(x_{i}-E(X))^{2}P(x_{i})$ for each $x_{i}$:

  • For $x = 0$: $(0 - 1.5)^{2}\times0.3=( - 1.5)^{2}\times0.3 = 2.25\times0.3=0.675$
  • For $x = 1$: $(1 - 1.5)^{2}\times0.25=( - 0.5)^{2}\times0.25 = 0.25\times0.25 = 0.0625$
  • For $x = 2$: $(2 - 1.5)^{2}\times0.1=(0.5)^{2}\times0.1 = 0.25\times0.1=0.025$
  • For $x = 3$: $(3 - 1.5)^{2}\times0.35=(1.5)^{2}\times0.35 = 2.25\times0.35 = 0.7875$ Then, $\text{Var}(X)=0.675 + 0.0625+0.025 + 0.7875=1.55$

Step3: Calculate standard - deviation

The standard deviation $\sigma=\sqrt{\text{Var}(X)}$. $\sigma=\sqrt{1.55}\approx1.24$

Answer:

a. $1.50$ b. $1.24$