identifying an unlikely estimate\nsample | sample mean\n1 | 16.8\n2 | 12.3\n3 | 19.0\n4 | 17.5\n5 | 18.2\n6…

identifying an unlikely estimate\nsample | sample mean\n1 | 16.8\n2 | 12.3\n3 | 19.0\n4 | 17.5\n5 | 18.2\n6 | 17.5\nlooking at the means of the samples, which of these values is least likely to be the mean of the population the samples were taken from?\n12.3\n18.4\n19.0\n19.5

identifying an unlikely estimate\nsample | sample mean\n1 | 16.8\n2 | 12.3\n3 | 19.0\n4 | 17.5\n5 | 18.2\n6 | 17.5\nlooking at the means of the samples, which of these values is least likely to be the mean of the population the samples were taken from?\n12.3\n18.4\n19.0\n19.5

Answer

Explanation:

Step1: Calculate grand sample mean

$\frac{16.8 +12.3 +19.0 +17.5 +18.2 +17.5}{6} = \frac{101.3}{6} \approx 16.88$

Step2: Find farthest value

Distance of 12.3 from 16.88: $|12.3 -16.88| = 4.58$ Distance of 18.4 from 16.88: $|18.4 -16.88| = 1.52$ Distance of 19.0 from 16.88: $|19.0 -16.88| = 2.12$ Distance of 19.5 from 16.88: $|19.5 -16.88| = 2.62$

Answer:

12.3