what is the interquartile range of this data set 1,5,27,29,34,37,48,61,72,84,96\na. 64\nb. 10\nc. 37\nd. 45

what is the interquartile range of this data set 1,5,27,29,34,37,48,61,72,84,96\na. 64\nb. 10\nc. 37\nd. 45

what is the interquartile range of this data set 1,5,27,29,34,37,48,61,72,84,96\na. 64\nb. 10\nc. 37\nd. 45

Answer

Explanation:

Step1: Arrange data in order

The data set is already in ascending - order: 1, 5, 27, 29, 34, 37, 48, 61, 72, 84, 96.

Step2: Find the median (Q2)

There are (n = 11) data points. The median is the (\left(\frac{n + 1}{2}\right))-th value. (\frac{11+1}{2}=6) - th value. So, (Q2=37).

Step3: Find the lower half and Q1

The lower half of the data is 1, 5, 27, 29, 34. There are (n_1 = 5) data points. The median of the lower - half ((Q1)) is the (\left(\frac{5 + 1}{2}\right))-th value, which is the 3 - rd value. So, (Q1 = 27).

Step4: Find the upper half and Q3

The upper half of the data is 48, 61, 72, 84, 96. There are (n_2 = 5) data points. The median of the upper - half ((Q3)) is the (\left(\frac{5+1}{2}\right))-th value, which is the 3 - rd value. So, (Q3 = 72).

Step5: Calculate the inter - quartile range (IQR)

The inter - quartile range is (IQR=Q3 - Q1). Substitute (Q1 = 27) and (Q3 = 72) into the formula: (IQR=72−27 = 45).

Answer:

D. 45