jace gathered the data in the table. he found the approximate line of best fit to be y = -0.7x + 2.36. what…

jace gathered the data in the table. he found the approximate line of best fit to be y = -0.7x + 2.36. what is the residual value when x = 5? -3.14 -0.86 0.86 3.14 x y 0 3 1 1 4 0 5 -2 7 -2

jace gathered the data in the table. he found the approximate line of best fit to be y = -0.7x + 2.36. what is the residual value when x = 5? -3.14 -0.86 0.86 3.14 x y 0 3 1 1 4 0 5 -2 7 -2

Answer

Explanation:

Step1: Calculate predicted value

Substitute $x = 5$ into $y=-0.7x + 2.36$. So, $y_{predicted}=-0.7\times5+2.36=-3.5 + 2.36=-1.14$.

Step2: Find residual value

Residual = Observed - Predicted. From the table, when $x = 5$, $y_{observed}=-2$. Then residual $=-2-(-1.14)=-2 + 1.14=-0.86$.

Answer:

$-0.86$