jace gathered the data in the table. he found the approximate line of best fit to be y = -0.7x + 2.36. what…

jace gathered the data in the table. he found the approximate line of best fit to be y = -0.7x + 2.36. what is the residual value when x = 5?\n| x | y |\n|----|----|\n| 0 | 3 |\n| 1 | 1 |\n| 4 | 0 |\n| 5 | -2 |\n| 7 | -2 |\n-3.14\n-0.86\n0.86\n3.14

jace gathered the data in the table. he found the approximate line of best fit to be y = -0.7x + 2.36. what is the residual value when x = 5?\n| x | y |\n|----|----|\n| 0 | 3 |\n| 1 | 1 |\n| 4 | 0 |\n| 5 | -2 |\n| 7 | -2 |\n-3.14\n-0.86\n0.86\n3.14

Answer

Explanation:

Step1: Find predicted y - value

Substitute $x = 5$ into $y=-0.7x + 2.36$. $y=-0.7\times5+2.36=-3.5 + 2.36=-1.14$

Step2: Calculate residual

Residual = Observed y - Predicted y. Observed y when $x = 5$ is $-2$. Residual=$-2-(-1.14)=-2 + 1.14=-0.86$

Answer:

$-0.86$