janna is making a prediction of the frequency of a key that is 12 keys from middle c. sound frequencies…

janna is making a prediction of the frequency of a key that is 12 keys from middle c. sound frequencies (piano)\n| number of keys above middle c | frequency (hz) |\n| ---- | ---- |\n| 0 | 277.18 |\n| 1 | 293.66 |\n| 2 | 311.13 |\n| 4 | 349.23 |\n| 8 | 440.00 |\nwhich best describes her prediction?\n○ interpolation, because a key that is 12 keys from middle c is within the data set\n○ interpolation, because a key that is 12 keys from middle c is outside the data set\n○ extrapolation, because a key that is 12 keys from middle c is within the data set\n○ extrapolation, because a key that is 12 keys from middle c is outside the data set

janna is making a prediction of the frequency of a key that is 12 keys from middle c. sound frequencies (piano)\n| number of keys above middle c | frequency (hz) |\n| ---- | ---- |\n| 0 | 277.18 |\n| 1 | 293.66 |\n| 2 | 311.13 |\n| 4 | 349.23 |\n| 8 | 440.00 |\nwhich best describes her prediction?\n○ interpolation, because a key that is 12 keys from middle c is within the data set\n○ interpolation, because a key that is 12 keys from middle c is outside the data set\n○ extrapolation, because a key that is 12 keys from middle c is within the data set\n○ extrapolation, because a key that is 12 keys from middle c is outside the data set

Answer

Answer:

extrapolation, because a key that is 12 keys from middle C is outside the data set

Brief Explanations:

The data set has keys 0, 1, 2, 4, 8 above middle - C. Since 12 is greater than 8, it's outside the data set. Predicting for a value outside the known data range is extrapolation.