janna is making a prediction of the frequency of a key that is 12 keys from middle c.\nsound frequencies…

janna is making a prediction of the frequency of a key that is 12 keys from middle c.\nsound frequencies (piano)\n| number of keys above middle c | frequency (hz) |\n| ---- | ---- |\n| 0 | 277.18 |\n| 1 | 293.66 |\n| 2 | 311.13 |\n| 4 | 349.23 |\n| 8 | 440.00 |\nwhich best describes her prediction?\ninterpolation, because a key that is 12 keys from middle c is within the data - set\ninterpolation, because a key that is 12 keys from middle c is outside the data - set\nextrapolation, because a key that is 12 keys from middle c is within the data - set\nextrapolation, because a key that is 12 keys from middle c is outside the data - set

janna is making a prediction of the frequency of a key that is 12 keys from middle c.\nsound frequencies (piano)\n| number of keys above middle c | frequency (hz) |\n| ---- | ---- |\n| 0 | 277.18 |\n| 1 | 293.66 |\n| 2 | 311.13 |\n| 4 | 349.23 |\n| 8 | 440.00 |\nwhich best describes her prediction?\ninterpolation, because a key that is 12 keys from middle c is within the data - set\ninterpolation, because a key that is 12 keys from middle c is outside the data - set\nextrapolation, because a key that is 12 keys from middle c is within the data - set\nextrapolation, because a key that is 12 keys from middle c is outside the data - set

Answer

Answer:

D. extrapolation, because a key that is 12 keys from middle C is outside the data - set

Brief Explanation:

Interpolation is for predicting values within the range of known data points. Extrapolation is for predicting values outside the known data - set. The data set has number of keys above middle C values of 0, 1, 2, 4, 8. Since 12 is outside this set, it is extrapolation.