joe sells bikes and gear at a used bicycle shop. the shop keeps records of each em sales. this list shows…

Explanation:

Step1: Arrange Monday's sales in ascending order

$11,16,24,34,43,183,210$ The number of data - points $n = 7$ (odd). Median is the $\left(\frac{n + 1}{2}\right)$-th value. So, median of Monday's sales is the 4th value, which is $34$. Mean of Monday's sales $\bar{x}_{1}=\frac{11 + 16+24+34+43+183+210}{7}=\frac{521}{7}\approx74.43$.

Step2: Arrange Wednesday's sales in ascending order

$6,12,17,30,71,83,90$ The number of data - points $n = 7$ (odd). Median is the 4th value, which is $30$. Mean of Wednesday's sales $\bar{x}_{2}=\frac{6 + 12+17+30+71+83+90}{7}=\frac{309}{7}\approx44.14$.

Step3: Arrange Thursday's sales in ascending order

$14,21,34,40,56,65,82$ The number of data - points $n = 7$ (odd). Median is the 4th value, which is $40$. Mean of Thursday's sales $\bar{x}_{3}=\frac{14+21+34+40+56+65+82}{7}=\frac{312}{7}\approx44.57$.

Step4: Arrange Friday's sales in ascending order

$8,13,17,86,190,211,225$ The number of data - points $n = 7$ (odd). Median is the 4th value, which is $86$. Mean of Friday's sales $\bar{x}_{4}=\frac{8 + 13+17+86+190+211+225}{7}=\frac{750}{7}\approx107.14$.

Step5: Analyze each statement

• The median of Wednesday's sales ($30$) is not the same as the median of Thursday's sales ($40$).
• The mean of Wednesday's sales ($\approx44.14$) is less than the mean of Monday's sales ($\approx74.43$).
• The median of Friday's sales ($86$) is higher than the medians of Monday ($34$), Wednesday ($30$), and Thursday ($40$).
• For Monday: median ($34$) < mean ($\approx74.43$); for Wednesday: median ($30$) < mean ($\approx44.14$); for Thursday: median ($40$) > mean ($\approx44.57$); for Friday: median ($86$) < mean ($\approx107.14$). So, the statement "For every shift, the median of Joe's sales is less than the mean" is not true.

Answer:

The median of Joe's sales on Wednesday is the same as the median on Thursday.