john sells frozen fruit bars at a stand in a park during the summer months. he records the average weekly…

john sells frozen fruit bars at a stand in a park during the summer months. he records the average weekly temperature and number of frozen fruit bars sold for 6 weeks.\n| temperature (°f) | fruit bars sold |\n| ---- | ---- |\n| 67 | 50 |\n| 71 | 54 |\n| 76 | 63 |\n| 76 | 65 |\n| 82 | 65 |\n| 87 | 100 |\nwhat type of correlation exists between the temperature and the number of fruit bars sold?\nwhat is the real - world meaning of the slope of the line of best fit for the given scenario?\nthere are approximately more fruit bars sold for every degree(s) the temperature rises.

john sells frozen fruit bars at a stand in a park during the summer months. he records the average weekly temperature and number of frozen fruit bars sold for 6 weeks.\n| temperature (°f) | fruit bars sold |\n| ---- | ---- |\n| 67 | 50 |\n| 71 | 54 |\n| 76 | 63 |\n| 76 | 65 |\n| 82 | 65 |\n| 87 | 100 |\nwhat type of correlation exists between the temperature and the number of fruit bars sold?\nwhat is the real - world meaning of the slope of the line of best fit for the given scenario?\nthere are approximately more fruit bars sold for every degree(s) the temperature rises.

Answer

Answer:

  1. Positive correlation
  2. There are approximately 2 more fruit bars sold for every 1 degree the temperature rises.

Explanation:

Step1: Analyze correlation type

As temperature increases, number of fruit - bars sold generally increases, so positive correlation.

Step2: Calculate slope approximation

Let $(x_1,y_1)=(67,50)$ and $(x_2,y_2)=(87,100)$. Slope $m=\frac{y_2 - y_1}{x_2 - x_1}=\frac{100 - 50}{87 - 67}=\frac{50}{20}=2.5\approx2$. So for every 1 - degree rise in temperature, approximately 2 more fruit bars are sold.