julio has two bags of gummy candies. one at a time, he randomly pulled 8 pineapple, 5 lime, and 7 strawberry…

julio has two bags of gummy candies. one at a time, he randomly pulled 8 pineapple, 5 lime, and 7 strawberry candies out of the first bag and put them back each time. he also randomly pulled 11 mango, 3 tamarind, and 6 watermelon candies out of the second bag and put them back each time. based on this information, what is the probability that julio will select a strawberry candy from the first bag and a tamarind candy from the second bag the next time he takes a candy from each bag? type a number in each box.

julio has two bags of gummy candies. one at a time, he randomly pulled 8 pineapple, 5 lime, and 7 strawberry candies out of the first bag and put them back each time. he also randomly pulled 11 mango, 3 tamarind, and 6 watermelon candies out of the second bag and put them back each time. based on this information, what is the probability that julio will select a strawberry candy from the first bag and a tamarind candy from the second bag the next time he takes a candy from each bag? type a number in each box.

Answer

Explanation:

Step1: Calculate probability of strawberry from first bag

The total number of candies in the first bag is $8 + 5+7=20$. The number of strawberry candies is 7. So the probability of selecting a strawberry - candy from the first bag, $P(S_1)=\frac{7}{20}$.

Step2: Calculate probability of tamarind from second bag

The total number of candies in the second bag is $11 + 3+6 = 20$. The number of tamarind candies is 3. So the probability of selecting a tamarind - candy from the second bag, $P(T_2)=\frac{3}{20}$.

Step3: Calculate joint probability

Since the events of selecting a candy from the first bag and a candy from the second bag are independent, the joint probability $P = P(S_1)\times P(T_2)$. So $P=\frac{7}{20}\times\frac{3}{20}=\frac{21}{400}$.

Answer:

$\frac{21}{400}$