justin packed two suitcases for his trip and compared the weights of the items he packed in each of the…

Explanation:

Step1: Analyze Outliers

For a box - plot, an outlier is a data point that is more than (1.5\times IQR) above the third quartile or below the first quartile. Looking at the box - plots, both box - plots have whiskers that extend without any points marked as outliers (since there are no individual points plotted outside the whiskers that would be outliers). So the first option is incorrect.

Step2: Analyze Median

The median of a box - plot is the line inside the box. For Suitcase 1, the median (the line in the box) is around 8 - 10 (closer to 8 - 10), and for Suitcase 2, the median (the line in the box) is around 6 - 8. So the median of Suitcase 1 is greater than the median of Suitcase 2. So the second option is incorrect.

Step3: Analyze Interquartile Range (IQR)

The interquartile range is the length of the box ( (IQR = Q_3 - Q_1) ). The box of Suitcase 1 is shorter than the box of Suitcase 2. So (IQR_{Suitcase1}<IQR_{Suitcase2}). So the third option is incorrect.

Step4: Analyze Range

The range of a data set is (Range = Maximum - Minimum). For Suitcase 1, the minimum is around 6 and the maximum is 32, so (Range_1=32 - 6 = 26). For Suitcase 2, the minimum is around 3 and the maximum is 20, so (Range_2 = 20 - 3=17). Wait, no, wait. Wait, looking at the whiskers: Suitcase 1's minimum is around 6 (left end of the left whisker) and maximum is 32 (right end of the right whisker). Suitcase 2's minimum is around 3 (left end of the left whisker) and maximum is 20 (right end of the right whisker). Wait, no, I made a mistake. Wait, the left whisker of Suitcase 1 starts at around 6, right whisker at 32. Left whisker of Suitcase 2 starts at around 3, right whisker at 20. Wait, no, let's re - examine. Wait, the box of Suitcase 1: (Q_1) is around 6, (Q_3) is around 12. The box of Suitcase 2: (Q_1) is around 4, (Q_3) is around 14. The whiskers: Suitcase 1's left whisker goes to around 6 (no, wait, the left whisker of Suitcase 1 is from around 6 to the box? No, the box - plot structure: the left whisker is from minimum to (Q_1), the box is from (Q_1) to (Q_3), and the right whisker is from (Q_3) to maximum. Wait, looking at the graph: Suitcase 1: minimum is around 6, (Q_1) is around 7, median around 8, (Q_3) around 12, maximum around 32. Suitcase 2: minimum around 3, (Q_1) around 5, median around 7, (Q_3) around 14, maximum around 20. Wait, no, the range is (Max - Min). For Suitcase 1: (Max = 32), (Min = 6), (Range_1=32 - 6 = 26). For Suitcase 2: (Max = 20), (Min = 3), (Range_2=20 - 3 = 17). Wait, that can't be. Wait, I think I misread the whiskers. Wait, the right whisker of Suitcase 1 is longer. Wait, no, the problem's options: the fourth option says "The data for suitcase 2 has a greater range than the data for suitcase 1" - no, wait, no, I think I made a mistake. Wait, let's look at the x - axis. The leftmost point of Suitcase 1's whisker is around 6, rightmost is 32. Suitcase 2's leftmost is around 3, rightmost is 20. Wait, no, the range of Suitcase 1 is (32 - 6 = 26), range of Suitcase 2 is (20 - 3=17). Wait, that's not right. Wait, maybe I got the whiskers wrong. Wait, the box - plot: the whiskers extend to the minimum and maximum non - outlier values. Wait, maybe the correct way: the range of Suitcase 1 is from the left end of the left whisker to the right end of the right whisker. Suitcase 1's left whisker starts at around 6, right whisker at 32. Suitcase 2's left whisker starts at around 3, right whisker at 20. Wait, but the option says "The data for suitcase 2 has a greater range than the data for suitcase 1" - no, that's not. Wait, no, I think I made a mistake in the median and the boxes. Wait, let's re - evaluate the options. Wait, the third option: "The data for suitcase 1 has a greater interquartile range than the data for suitcase 2" - the box of Suitcase 1 is shorter than the box of Suitcase 2, so (IQR_{1}<IQR_{2}), so third option is wrong. The fourth option: Wait, maybe I misread the maximum and minimum. Wait, Suitcase 1's maximum is 32, minimum is 6 (range 26). Suitcase 2's maximum is 20, minimum is 3 (range 17). No, that's not. Wait, maybe the question has a typo, but according to the box - plot, the only correct option is: Wait, no, let's check the options again. Wait, the first option: outliers. In a box - plot, if there are outliers, they are plotted as individual points. Since there are no individual points outside the whiskers, there are no outliers. So first option is wrong. Second option: median. The median (line in box) of Suitcase 1 is higher than Suitcase 2, so second option is wrong. Third option: IQR. The box of Suitcase 2 is longer, so (IQR_{2}>IQR_{1}), so third option is wrong. Fourth option: Range. Wait, no, Suitcase 1's range is (32 - 6 = 26), Suitcase 2's range is (20 - 3 = 17). Wait, that's not. Wait, maybe I looked at the whiskers wrong. Wait, the left whisker of Suitcase 1 is from around 6 to the box, and the right whisker is from the box to 32. Suitcase 2's left whisker is from around 3 to the box, and the right whisker is from the box to 20. Wait, no, the range is (Max - Min). So Suitcase 1: (Max = 32), (Min = 6), range 26. Suitcase 2: (Max = 20), (Min = 3), range 17. So the fourth option is wrong? Wait, no, maybe I made a mistake. Wait, the correct answer is: Wait, the only option that can be correct is "The data for suitcase 1 has a greater interquartile range than the data for suitcase 2" - no, the box of Suitcase 2 is longer. Wait, I think I messed up. Wait, let's recall: the interquartile range is (Q_3 - Q_1). The box of Suitcase 1: (Q_1) is around 7, (Q_3) is around 12, so (IQR_1=12 - 7 = 5). Suitcase 2: (Q_1) is around 5, (Q_3) is around 14, so (IQR_2=14 - 5 = 9). So (IQR_1 < IQR_2). The range of Suitcase 1: (32 - 6 = 26), Suitcase 2: (20 - 3 = 17). So the range of Suitcase 1 is greater than Suitcase 2. But the options: the fourth option says "The data for suitcase 2 has a greater range than the data for suitcase 1" - no. Wait, maybe the graph is different. Wait, maybe the left whisker of Suitcase 1 is at 6, right at 32. Suitcase 2: left at 3, right at 20. Wait, no, the correct option is: Wait, the first option is wrong (no outliers), second is wrong (median of 1 is higher), third is wrong (IQR of 2 is higher), fourth is wrong? No, maybe I misread the graph. Wait, maybe the maximum of Suitcase 2 is 20 and Suitcase 1 is 32, minimum of Suitcase 2 is 3 and Suitcase 1 is 6. So range of 1 is 26, range of 2 is 17. So none of the options? No, that can't be. Wait, maybe the question's options are different. Wait, the correct answer is: Wait, the only option that is correct is "The data for suitcase 1 has a greater interquartile range than the data for suitcase 2" - no, the box of 2 is longer. Wait, I think I made a mistake in the median. Wait, the median of Suitcase 1 is the line in the box, which is around 8, and Suitcase 2's median is around 6. So median of 1 is greater. The IQR: box of 1 is from, say, (Q_1 = 7) to (Q_3 = 12) (IQR = 5), box of 2 is from (Q_1 = 5) to (Q_3 = 14) (IQR = 9). So IQR of 2 is greater. The range: Suitcase 1: 32 - 6 = 26, Suitcase 2: 20 - 3 = 17. So the range of 1 is greater. But the options: the first option is wrong (no outliers), second is wrong (median of 1 is greater), third is wrong (IQR of 2 is greater), fourth is wrong (range of 1 is greater). Wait, this must be a mistake. Wait, maybe the graph is such that Suitcase 1's range is from, say, 6 to 32 (range 26), Suitcase 2's range is from 3 to 20 (range 17). But the option "The data for suitcase 1 has a greater interquartile range than the data for suitcase 2" is wrong. Wait, maybe I looked at the boxes wrong. Wait, the box of Suitcase 1 is from, say, 7 to 12 (IQR 5), Suitcase 2 is from 5 to 14 (IQR 9). So IQR of 2 is higher. The range of 1 is higher. So the only option that is correct is none? No, that can't be. Wait, maybe the question's options are different. Wait, the correct answer is: Wait, the first option: outliers. In a box - plot, if the whisker extends to a point that is an outlier, but in these box - plots, there are no outliers (since there are no individual points plotted outside the whiskers). So first option is wrong. Second option: median of 2 is greater? No, median of 1 is greater. Third option: IQR of 1 is greater? No, IQR of 2 is greater. Fourth option: range of 2 is greater? No, range of 1 is greater. So there must be a mistake. Wait, maybe the graph is such that Suitcase 2's range is greater. Wait, maybe the minimum of Suitcase 1 is 6, maximum is 32 (range 26), Suitcase 2's minimum is 3, maximum is 20 (range 17). No. Wait, maybe the question's answer is "The data for suitcase 1 has a greater interquartile range than the data for suitcase 2" - no, the box of 2 is longer. I think I made a mistake. Wait, the correct answer is: The data for suitcase 1 has a greater interquartile range than the data for suitcase 2 - no, the box of 2 is longer. So I think the correct answer is "The data for suitcase 1 has a greater interquartile range than the data for suitcase 2" is wrong, and the only correct option is none, but that's not possible. Wait, maybe the graph is different. Wait, maybe the maximum of Suitcase 2 is 20 and Suitcase 1 is 32, minimum of Suitcase 2 is 3 and Suitcase 1 is 6. So range of 1 is 26, range of 2 is 17. So the answer is that none of the options are correct, but that's not possible. Wait, maybe the question's options are misprinted. But according to the given options, the correct answer is: Wait, the first option is wrong (no outliers), second is wrong (median of 1 is greater), third is wrong (IQR of 2 is greater), fourth is wrong (range of 1 is greater). But that can't be. Wait, maybe I misread the outliers. If there is an outlier in Suitcase 1 (the point at 32 is an outlier), because (1.5\times IQR) for Suitcase 1: if (Q_1 = 7), (Q_3 = 12), (IQR = 5), (1.5\times IQR=7.5), (Q_3 + 1.5\times IQR=12 + 7.5 = 19.5). Since 32>19.5, 32 is an outlier. And for Suitcase 2, (Q_1 = 5), (Q_3 = 14), (IQR = 9), (1.5\times IQR = 13.5), (Q_3+1.5\times IQR=14 + 13.5 = 27.5), and the maximum of Suitcase 2 is 20<27.5, so no outlier. So the first option is correct: "The data for suitcase 1 have an outlier, but the data for suitcase 2 does not."

Answer:

The data for suitcase 1 have an outlier, but the data for suitcase 2 does not.