kiley gathered the data in the table. she found the approximate line of best fit to be y = 1.6x - 4. what is…

kiley gathered the data in the table. she found the approximate line of best fit to be y = 1.6x - 4. what is the residual value when x = 3?\n| x | y |\n|----|----|\n| 0 | -3 |\n| 2 | -1 |\n| 3 | -1 |\n| 5 | 5 |\n| 6 | 6 |\n-1.8\n-0.2\n0.2\n1.8

kiley gathered the data in the table. she found the approximate line of best fit to be y = 1.6x - 4. what is the residual value when x = 3?\n| x | y |\n|----|----|\n| 0 | -3 |\n| 2 | -1 |\n| 3 | -1 |\n| 5 | 5 |\n| 6 | 6 |\n-1.8\n-0.2\n0.2\n1.8

Answer

Answer:

-0.2

Explanation:

Step1: Calculate predicted value

When $x = 3$, substitute into $y = 1.6x-4$. So $y_{predicted}=1.6\times3 - 4=4.8 - 4 = 0.8$.

Step2: Find actual value

From the table, when $x = 3$, $y_{actual}=-1$.

Step3: Calculate residual

Residual = $y_{actual}-y_{predicted}=-1 - 0.8=-0.2$.