in a large population, 66% of the people have been vaccinated. if 5 people are randomly selected, what is…

in a large population, 66% of the people have been vaccinated. if 5 people are randomly selected, what is the probability that at least one of them has been vaccinated? give your answer as a decimal to 4 places. question help: message instructor
Answer
Explanation:
Step1: Find the probability of a person not being vaccinated
The probability of a person being vaccinated is $p = 0.66$. So the probability of a person not being vaccinated is $q=1 - p=1 - 0.66 = 0.34$.
Step2: Find the probability that none of the 5 people are vaccinated
Since the selections are independent events, the probability that none of the 5 people are vaccinated is $q^5$. Substituting $q = 0.34$ into the formula, we get $(0.34)^5=0.34\times0.34\times0.34\times0.34\times0.34 = 0.0045435424$.
Step3: Find the probability that at least one person is vaccinated
The probability that at least one person is vaccinated is the complement of the event that none of the people are vaccinated. Let $P(X\geq1)$ be the probability that at least one person is vaccinated. Then $P(X\geq1)=1 - P(X = 0)$. Since $P(X = 0)=(0.34)^5$, we have $P(X\geq1)=1-(0.34)^5=1 - 0.0045435424 = 0.9954564576$.
Answer:
$0.9955$