leah needs to shade \\(\\frac{1}{5}\\) of the 20 small squares in the grid. leahs work is shown. what should…

leah needs to shade \\(\\frac{1}{5}\\) of the 20 small squares in the grid. leahs work is shown. what should leah do to correct her work? add shading to 1 more small square. add shading to 2 more small squares. remove shading from 1 small square. remove shading from 2 small squares.
Answer
Explanation:
Step1: Calculate the target number of shaded squares.
To find (\frac{1}{5}) of 20, we use the formula (\frac{1}{5} \times 20). (\frac{1}{5} \times 20 = 4)
Step2: Count the current number of shaded squares.
Looking at the grid, we can see that there are 5 shaded squares (let's count: first row: 2, second row: 2, third row: 1; total (2 + 2+ 1 = 5)).
Step3: Determine the correction needed.
Since the target is 4 and we currently have 5, we need to remove shading from (5 - 4 = 1) small square? Wait, no, wait. Wait, wait, let's recount. Wait the grid: first row: two blue (left and right), second row: two blue (middle two), third row: one blue (middle). So total: 2 + 2 + 1 = 5. The target is 4. So we need to remove (5 - 4 = 1)? Wait no, wait the options: "Remove shading from 1 small square" is an option? Wait no, wait the options: "Remove shading from 1 small square" is option C? Wait the options are:
-
Add shading to 1 more small square.
-
Add shading to 2 more small squares.
-
Remove shading from 1 small square.
-
Remove shading from 2 small squares.
Wait, target is 4. Current shaded: let's count again. First row: two blue (columns 1 and 5). Second row: two blue (columns 2 and 4). Third row: one blue (column 3). So total: 2 (row1) + 2 (row2) + 1 (row3) = 5. So 5 - 4 = 1. So we need to remove 1. Wait but wait, the options: "Remove shading from 1 small square" is option 3. Wait but let's check again. Wait (\frac{1}{5}) of 20 is 4. Current shaded: 5. So 5 - 4 = 1. So we need to remove 1. So the correct option is "Remove shading from 1 small square." Wait but wait, maybe I miscounted. Wait the grid: let's see the grid structure. The grid has 4 rows? No, the grid has 3 rows? Wait the image: first row: 5 squares (dashed lines), second row: 5, third row: 5, fourth row: 5? Wait no, the image shows a grid with 4 rows? Wait no, the original problem says 20 small squares. 20 squares: 4 rows of 5? Wait no, 5 columns and 4 rows? 54=20. So rows: 4? Wait the image shows 3 rows? Wait maybe the grid is 5 columns and 4 rows? Wait the problem says 20 small squares. So 5 columns and 4 rows (54=20). Let's look at the image again. The image shows:
Row 1: [blue][white][white][white][blue]
Row 2: [white][blue][white][blue][white]
Row 3: [white][white][blue][white][white]
Row 4: [white][white][white][white][white]
Wait, so row 1: 2 blue, row 2: 2 blue, row 3: 1 blue. Total: 2 + 2 + 1 = 5. Rows: 4? Wait row 4 is all white. So total squares: 5*4=20. So shaded squares: 5. Target: 4. So 5 - 4 = 1. So we need to remove 1. So the correct option is "Remove shading from 1 small square." Wait but the options: "Remove shading from 1 small square" is option 3. Wait the options are:
A. Add shading to 1 more small square.
B. Add shading to 2 more small squares.
C. Remove shading from 1 small square.
D. Remove shading from 2 small squares.
So the correct answer is C. Remove shading from 1 small square. Wait but wait, let's check again. (\frac{1}{5}) of 20 is 4. Current shaded: 5. So 5 - 4 = 1. So we need to remove 1. So the answer is "Remove shading from 1 small square."
Answer:
C. Remove shading from 1 small square.