lesson 11 practice problems\n1 in science class, clare and lin estimate the mass of eight different objects…

lesson 11 practice problems\n1 in science class, clare and lin estimate the mass of eight different objects that actually weigh 2,000 grams each. some summary statistics\nclare\n - mean: 2,000 grams\n - mad: 275 grams\n - median: 2,000 grams\n - iqr: 500 grams\nlin\n - mean: 2,000 grams\n - mad: 225 grams\n - median: 1,950 grams\n - iqr: 350 grams\nwhich student was better at estimating the mass of the objects? explain your reasoning.\n2 a reporter counts the number of times a politician talks about jobs in campaign speeches. what is the mad of the data represented in the dot - plot?\n number of mentions of \jobs\\na 1.1 mentions\nb 2 mentions\nc 2.5 mentions\nd 5.5 mentions

lesson 11 practice problems\n1 in science class, clare and lin estimate the mass of eight different objects that actually weigh 2,000 grams each. some summary statistics\nclare\n - mean: 2,000 grams\n - mad: 275 grams\n - median: 2,000 grams\n - iqr: 500 grams\nlin\n - mean: 2,000 grams\n - mad: 225 grams\n - median: 1,950 grams\n - iqr: 350 grams\nwhich student was better at estimating the mass of the objects? explain your reasoning.\n2 a reporter counts the number of times a politician talks about jobs in campaign speeches. what is the mad of the data represented in the dot - plot?\n number of mentions of \jobs\\na 1.1 mentions\nb 2 mentions\nc 2.5 mentions\nd 5.5 mentions

Answer

Explanation:

Step1: Understand the concept of MAD

MAD (Mean - Absolute - Deviation) measures the average distance between each data point and the mean. A lower MAD indicates that the data points are closer to the mean, meaning more consistent and accurate estimates.

Step2: Compare the MADs of Clare and Lin

Clare has a MAD of 275 grams and Lin has a MAD of 225 grams. Since 225 < 275, Lin's estimates are on average closer to the actual mass of 2000 grams.

Answer:

Lin was better at estimating the mass of the objects because Lin has a lower MAD (225 grams) compared to Clare's MAD (275 grams), which means Lin's estimates were on average closer to the actual mass of 2000 grams for each object.

Explanation for sub - question 2:

Step1: Calculate the mean

Count the number of data points. There are 1 + 1+ 3+ 3+ 1+ 1 = 10 data points. The sum of the data points is (3\times1 + 4\times1+5\times3 + 6\times3+7\times1+8\times1=3 + 4+15 + 18+7+8 = 55). The mean (\bar{x}=\frac{55}{10}=5.5).

Step2: Calculate the absolute - deviations

For (x = 3), the absolute - deviation is (|3 - 5.5|=2.5); for (x = 4), (|4 - 5.5| = 1.5); for (x = 5), (|5 - 5.5|=0.5); for (x = 6), (|6 - 5.5| = 0.5); for (x = 7), (|7 - 5.5|=1.5); for (x = 8), (|8 - 5.5| = 2.5).

Step3: Calculate the MAD

Multiply each absolute - deviation by the frequency of the data point: ((2.5\times1+1.5\times1 + 0.5\times3+0.5\times3+1.5\times1+2.5\times1)\div10=(2.5 + 1.5+1.5 + 1.5+1.5+2.5)\div10 = 11\div10 = 1.1)

Answer:

A. 1.1 mentions