let (p(u)=0.48) and (p(v)=0.25). events (u) and (v) are mutually exclusive. find (p(u or v).\n0.73\n0.23\n1.9…

let (p(u)=0.48) and (p(v)=0.25). events (u) and (v) are mutually exclusive. find (p(u or v).\n0.73\n0.23\n1.92\n - 0.23\n0.520833333333333\n0.12\nquestion help: message instructor
Answer
Explanation:
Step1: Recall probability formula for mutually - exclusive events
For mutually exclusive events (U) and (V), (P(U\ or\ V)=P(U)+P(V)).
Step2: Substitute given values
We know that (P(U) = 0.48) and (P(V)=0.25), so (P(U\ or\ V)=0.48 + 0.25).
Step3: Calculate the result
(0.48+0.25 = 0.73).
Answer:
A. 0.73