a letter is randomly selected from the word accommodation. which events have the same likelihood of…

a letter is randomly selected from the word accommodation. which events have the same likelihood of occurring as selecting an a? select all that apply.\na) selecting a d\nb) selecting an o\nc) selecting a c\nd) selecting a t\ne) selecting an m
Answer
Explanation:
Step1: Count total letters
The word "ACCOMMODATION" has 13 letters.
Step2: Count number of 'A's
There are 2 'A's. So the probability of selecting an 'A' is $\frac{2}{13}$.
Step3: Count number of each letter in options
- A) There is 1 'D', probability of selecting a 'D' is $\frac{1}{13}$.
- B) There are 2 'O's, probability of selecting an 'O' is $\frac{2}{13}$.
- C) There are 2 'C's, probability of selecting a 'C' is $\frac{2}{13}$.
- D) There is 1 'T', probability of selecting a 'T' is $\frac{1}{13}$.
- E) There are 2 'M's, probability of selecting an 'M' is $\frac{2}{13}$.
Answer:
B. selecting an O, C. selecting a C, E. selecting an M