lewis is rolling a 10 - sided die 250 times. each side of the die is labeled with a number 1 - 10. based on…
lewis is rolling a 10 - sided die 250 times. each side of the die is labeled with a number 1 - 10. based on the theoretical probability, how many times would lewis be expected to roll a multiple of 3?\no 25\no 30\no 75\no 83
Answer
Explanation:
Step1: Find probability of rolling a multiple of 3
The multiples of 3 from 1 - 10 are 3, 6, 9. So there are 3 favorable outcomes out of 10 total outcomes. The probability $P$ of rolling a multiple of 3 on a single roll is $P=\frac{3}{10}$.
Step2: Calculate expected number of times
The expected number of times $E$ of rolling a multiple of 3 in 250 rolls is found by multiplying the probability by the number of trials. So $E = \frac{3}{10}\times250$. $E=\frac{3\times250}{10}= 75$.
Answer:
75