a librarian chooses seven holiday books from a selection of ten to be displayed in the window of the…

a librarian chooses seven holiday books from a selection of ten to be displayed in the window of the library. in how many different ways can she choose the group of seven books?
Answer
Explanation:
Step1: Identify combination formula
The formula for combinations is $C(n,r)=\frac{n!}{r!(n - r)!}$, where $n$ is the total number of items, and $r$ is the number of items to be chosen. Here, $n = 10$ and $r=7$.
Step2: Calculate factorial values
We know that $n!=n\times(n - 1)\times\cdots\times1$. So, $10! = 10\times9\times8\times7\times6\times5\times4\times3\times2\times1$, $7! = 7\times6\times5\times4\times3\times2\times1$, and $(10 - 7)!=3!=3\times2\times1$. Then $C(10,7)=\frac{10!}{7!(10 - 7)!}=\frac{10!}{7!3!}=\frac{10\times9\times8\times7!}{7!\times3\times2\times1}$.
Step3: Simplify the expression
The $7!$ terms in the numerator and denominator cancel out. We get $\frac{10\times9\times8}{3\times2\times1}=\frac{720}{6}=120$.
Answer:
120