linda and greg go swimming.\n- linda swims \\(\\frac{1}{20}\\) of a mile every minute.\n- greg swims…

Answer:

A. Linda is faster by $\frac{1}{4}$ mile per minute.

Explanation:

Step1: Calculate Linda's speed

Linda's speed = $\frac{1}{20}$ mile/minute

Step2: Calculate Greg's speed

Greg's speed = $\frac{3/10}{6} = \frac{3}{10} \times \frac{1}{6} = \frac{1}{20}$ mile/minute? No, wait correction: Wait $\frac{3}{10}$ mile in 6 minutes, so per minute is $\frac{3}{10} \div 6 = \frac{3}{10} \times \frac{1}{6} = \frac{1}{20}$? No, wait no—wait $\frac{1}{20}$ is 0.05, $\frac{3}{10}$ is 0.3, 0.3/6=0.05. Wait but option A says Linda faster by 1/4. Wait wait, did I misread? Oh wait no—wait Linda's speed: $\frac{1}{20}$? No wait no, wait $\frac{1}{20}$ is 0.05, but 1/4 is 0.25. Wait wait maybe typo? Wait no, wait let's recheck: Oh no! Wait Linda swims $\frac{1}{20}$ per minute? No wait no—wait $\frac{1}{20}$ is 0.05, Greg $\frac{3}{10}$ in 6 minutes is 0.05. But that can't be. Wait wait maybe I misread the problem: Oh wait no—wait is Linda's speed $\frac{1}{2}$ per minute? No, the problem says $\frac{1}{20}$. Wait no, maybe the problem has a typo, but according to the options, the only possible correct one if there's a typo (like Linda's speed is $\frac{1}{5}$ per minute: $\frac{1}{5}=0.2$, Greg 0.05, difference 0.15 no. Wait no—wait wait $\frac{1}{4}$ is 0.25. Oh wait wait, maybe Greg's speed is $\frac{3}{10}$ per 6 minutes is $\frac{1}{20}$, Linda's speed is $\frac{1}{5}$ per minute: $\frac{1}{5} - \frac{1}{20} = \frac{3}{20}$ no. Wait I think there's a mistake in my calculation earlier, but according to standard problems like this, the intended answer is A. Wait no—wait no, let's go back: Oh! Wait I think I misread Linda's speed: Oh no! The problem says Linda swims $\frac{1}{2}$ of a mile every minute? No, it says $\frac{1}{20}$. Wait no, maybe the problem was written wrong, but according to the options, the answer is A. Wait no—wait no, let's do it again:

Wait Linda's speed: $v_L = \frac{1}{20}$ mile/min. Greg's speed: $v_G = \frac{3/10}{6} = \frac{1}{20}$ mile/min. That's same, but option C says same. Wait why? Oh! Oh right! So the correct answer is C. Because both are $\frac{1}{20}$ mile per minute. Oh I see! I made a mistake earlier thinking about typo. So the correct answer is C.

Answer:

C. Linda and Greg have the same speed.

Explanation:

Step1: Compute Linda's speed

Linda's speed = $\frac{1}{20}$ mile/minute

Step2: Compute Greg's speed

Greg's speed = $\frac{3/10}{6} = \frac{1}{20}$ mile/minute

Step3: Compare speeds

Both speeds equal, so C is true.