lola pulls two marbles from a bag containing four red marbles, four blue marbles, and 12 yellow marbles…

lola pulls two marbles from a bag containing four red marbles, four blue marbles, and 12 yellow marbles without replacing them. what is the probability that she pulled out a red marble first and a yellow marble second? express your answer in decimal form, rounded to the nearest hundredth. 0 0.09 0 0.13 0 0.25 0 0.32
Answer
Explanation:
Step1: Calculate total number of marbles
The total number of marbles is $4 + 4+12=20$.
Step2: Calculate probability of first - red marble
The probability of pulling a red marble first is $\frac{4}{20}$ since there are 4 red marbles out of 20 total marbles.
Step3: Calculate probability of second - yellow marble
After pulling a red marble first (without replacement), there are now 19 marbles left. The probability of pulling a yellow marble second is $\frac{12}{19}$ since there are 12 yellow marbles out of the remaining 19 marbles.
Step4: Calculate combined probability
The probability of both events happening is the product of their individual probabilities. So $P=\frac{4}{20}\times\frac{12}{19}=\frac{48}{380}\approx0.13$.
Answer:
0.13