louden county wildlife conservancy counts butterflies each year. data over the last three years regarding…

louden county wildlife conservancy counts butterflies each year. data over the last three years regarding four types of butterflies are shown below. what is the average number of variegated fritillaries for all three samples?\n\nlouden county butterfly count\n| | 2009 | 2010 | 2011 |\n|--|--|--|--|--|\n| meadow fritillary | 5 | meadow fritillary | 34 | meadow fritillary | 14 |\n| variegated fritillary | 7 | variegated fritillary | 95 | variegated fritillary | 63 |\n| zebra swallowtail | 33 | zebra swallowtail | 21 | zebra swallowtail | 10 |\n| eastern - tailed blue | 242 | eastern - tailed blue | 168 | eastern - tailed blue | 170 |\n\n55\n83\n106\n165

louden county wildlife conservancy counts butterflies each year. data over the last three years regarding four types of butterflies are shown below. what is the average number of variegated fritillaries for all three samples?\n\nlouden county butterfly count\n| | 2009 | 2010 | 2011 |\n|--|--|--|--|--|\n| meadow fritillary | 5 | meadow fritillary | 34 | meadow fritillary | 14 |\n| variegated fritillary | 7 | variegated fritillary | 95 | variegated fritillary | 63 |\n| zebra swallowtail | 33 | zebra swallowtail | 21 | zebra swallowtail | 10 |\n| eastern - tailed blue | 242 | eastern - tailed blue | 168 | eastern - tailed blue | 170 |\n\n55\n83\n106\n165

Answer

Explanation:

Step1: Identify the counts

The number of Variegated Fritillaries in 2009 is 7, in 2010 is 95 and in 2011 is 63.

Step2: Calculate the sum

$7 + 95+63=165$

Step3: Calculate the average

The average is $\frac{165}{3}=55$

Answer:

55