when a man observed a sobriety checkpoint conducted by a police department, he saw 652 drivers were screened…
when a man observed a sobriety checkpoint conducted by a police department, he saw 652 drivers were screened and 4 were arrested for driving while intoxicated. based on those results, we can estimate that p(w)=0.00613, where w denotes the event of screening a driver and getting someone who is intoxicated. what does p(\\overline{w}) denote, and what is its value? what does p(\\overline{w}) represent? a. p(\\overline{w}) denotes the probability of screening a driver and finding that he or she is not intoxicated. b. p(\\overline{w}) denotes the probability of a driver passing through the sobriety checkpoint. c. p(\\overline{w}) denotes the probability of driver being intoxicated. d. p(\\overline{w}) denotes the probability of screening a driver and finding that he or she is intoxicated.
Answer
Brief Explanations:
In probability, $\overline{W}$ is the complement of event $W$. Since $W$ is the event of screening a driver and getting someone who is intoxicated, $\overline{W}$ is the event of screening a driver and getting someone who is not intoxicated. The probability of an event and its complement satisfy $P(W)+P(\overline{W}) = 1$.
Answer:
A. P($\overline{W}$) denotes the probability of screening a driver and finding that he or she is not intoxicated.
First, we know that $P(W)=0.00613$. Since $P(W)+P(\overline{W}) = 1$, we can calculate $P(\overline{W})$ as follows: $P(\overline{W})=1 - P(W)$ $P(\overline{W})=1 - 0.00613=0.99387$