mariah works at a zoo. she was looking at some data showing the masses of their 5 african elephants. the…

mariah works at a zoo. she was looking at some data showing the masses of their 5 african elephants. the mean mass of the elephants was 3,800 kg, and the median mass was 3,600 kg. the heaviest elephant, named omar, was recorded as 6,000 kg. mariah found out that omars mass was recorded incorrectly, and that omar actually weighed 7,000 kg. how will omars mass increasing affect the mean and median? choose 1 answer: a both the mean and median will increase. b the mean will stay the same, and the median will increase. c the mean will increase, and the median will decrease. d the mean will increase, and the median will stay the same.

mariah works at a zoo. she was looking at some data showing the masses of their 5 african elephants. the mean mass of the elephants was 3,800 kg, and the median mass was 3,600 kg. the heaviest elephant, named omar, was recorded as 6,000 kg. mariah found out that omars mass was recorded incorrectly, and that omar actually weighed 7,000 kg. how will omars mass increasing affect the mean and median? choose 1 answer: a both the mean and median will increase. b the mean will stay the same, and the median will increase. c the mean will increase, and the median will decrease. d the mean will increase, and the median will stay the same.

Answer

Explanation:

Step1: Recall the formula for the mean

The mean $\bar{x}=\frac{\sum_{i = 1}^{n}x_{i}}{n}$. Here $n = 5$ (the number of elephants). When the mass of one data - point (Omar's mass) increases, and the other 4 masses remain the same, the sum $\sum_{i = 1}^{n}x_{i}$ increases. Since $n$ is constant, the mean $\bar{x}$ will increase.

Step2: Recall the concept of the median

The median is the middle - value when the data is arranged in ascending or descending order. There are 5 data - points. The median is the 3rd value when the masses of the 5 elephants are arranged in order. Since Omar is the heaviest elephant, changing its mass (from 6000 kg to 7000 kg) does not change the position of the middle - value among the 5 masses. So the median remains the same.

Answer:

D. The mean will increase, and the median will stay the same.