when marques commutes to work, the amount of time it takes him to arrive is normally distributed with a mean…

when marques commutes to work, the amount of time it takes him to arrive is normally distributed with a mean of 37 minutes and a standard deviation of 4.5 minutes. using the empirical rule, what percentage of his commutes will be between 23.5 and 50.5 minutes?

when marques commutes to work, the amount of time it takes him to arrive is normally distributed with a mean of 37 minutes and a standard deviation of 4.5 minutes. using the empirical rule, what percentage of his commutes will be between 23.5 and 50.5 minutes?

Answer

Explanation:

Step1: Calculate number of standard - deviations from the mean

First, find how many standard deviations 23.5 and 50.5 are from the mean. The formula for the z - score is $z=\frac{x-\mu}{\sigma}$, where $\mu$ is the mean, $\sigma$ is the standard deviation, and $x$ is the value. For $x = 23.5$, $\mu=37$, and $\sigma = 4.5$, $z_1=\frac{23.5 - 37}{4.5}=\frac{- 13.5}{4.5}=-3$. For $x = 50.5$, $\mu = 37$, and $\sigma=4.5$, $z_2=\frac{50.5 - 37}{4.5}=\frac{13.5}{4.5}=3$.

Step2: Apply the empirical rule

The empirical rule for a normal distribution states that approximately 99.7% of the data lies within 3 standard deviations of the mean. That is, $P(\mu - 3\sigma<X<\mu + 3\sigma)\approx99.7%$. Since $23.5=\mu - 3\sigma$ and $50.5=\mu + 3\sigma$, the percentage of his commutes between 23.5 and 50.5 minutes is 99.7%.

Answer:

99.7%