math 003. fall 2025\nquestion 17, 7.3.45 part 2 of 3\nhw score: 50%, 23 of 46 points\npoints: 0 of 1\nuse…

math 003. fall 2025\nquestion 17, 7.3.45 part 2 of 3\nhw score: 50%, 23 of 46 points\npoints: 0 of 1\nuse the display of data to find the mean, median, and mode.\nthe mean of the data is 12.0 (type a whole number or decimal rounded to the nearest tenth as needed.)\nthe median of the data is (type a whole number or decimal rounded to the nearest tenth as needed.)

math 003. fall 2025\nquestion 17, 7.3.45 part 2 of 3\nhw score: 50%, 23 of 46 points\npoints: 0 of 1\nuse the display of data to find the mean, median, and mode.\nthe mean of the data is 12.0 (type a whole number or decimal rounded to the nearest tenth as needed.)\nthe median of the data is (type a whole number or decimal rounded to the nearest tenth as needed.)

Answer

Explanation:

Step1: Determine total frequency

From the histogram, frequencies for scores 10 - 14 are 5, 6, 9, 5, 4 respectively. Total frequency $n=5 + 6+9+5+4=29$.

Step2: Find position of median

Since $n = 29$ (odd), the median position is $\frac{n + 1}{2}=\frac{29+1}{2}=15$ - th value.

Step3: Cumulative - frequency to find median

Cumulative frequencies: For score 10, $CF_1=5$; for score 11, $CF_2=5 + 6=11$; for score 12, $CF_3=5+6 + 9=20$. The 15 - th value falls within the score of 12.

Answer:

12.0