the means and mean absolute deviations of the individual times of members on two 4 x 400 - meter relay track…

the means and mean absolute deviations of the individual times of members on two 4 x 400 - meter relay track teams are shown in the table below.\n\n| | means and mean absolute deviations of individual times of members of 4 x 400 - meter relay track teams | |\n|--|--|--|\n| | team a | team b |\n| mean | 59.32 s | 59.1 s |\n| mean absolute deviation | 1.5 s | 2.4 s |\n\nwhat is the ratio of the difference in the means of the two teams to the mean absolute deviation of team b?\n0.09\n0.15\n0.25\n0.65

the means and mean absolute deviations of the individual times of members on two 4 x 400 - meter relay track teams are shown in the table below.\n\n| | means and mean absolute deviations of individual times of members of 4 x 400 - meter relay track teams | |\n|--|--|--|\n| | team a | team b |\n| mean | 59.32 s | 59.1 s |\n| mean absolute deviation | 1.5 s | 2.4 s |\n\nwhat is the ratio of the difference in the means of the two teams to the mean absolute deviation of team b?\n0.09\n0.15\n0.25\n0.65

Answer

Explanation:

Step1: Calculate difference in means

$|59.32 - 59.1|= 0.22$

Step2: Calculate the ratio

$\frac{0.22}{2.4}\approx0.09$

Answer:

0.09