3.2 measures of spread: standard deviation and variance\nconcrete formulated for use in commercial…

3.2 measures of spread: standard deviation and variance\nconcrete formulated for use in commercial structures is designed to withstand pressures of 4000 pounds per square inch. the data set below represents the strength of 20 randomly selected samples of concrete. click on the data button shown below to display the data and copy and paste it into a statistical software package. then compute the mean and standard deviation rounding your answers to 1 decimal place.\ndata\nstrength\n4444\n4085\n4078\n4444\n4001\n4322\n4345\n4398\n4175\n4319\n4211\n4239\n4133\n3922\n4494\n4172\n4263\n3911\n3935\n3976
Answer
Explanation:
Step1: Calculate the sum of data
Let the data - set be (x_1,x_2,\cdots,x_{20}). The sum (S=\sum_{i = 1}^{20}x_i=4444 + 4085+4078+4444+4001+4322+4345+4398+4175+4319+4211+4239+4133+3922+4494+4172+4263+3911+3935+3976 = 83714)
Step2: Calculate the mean (\bar{x})
The formula for the mean of a sample is (\bar{x}=\frac{\sum_{i = 1}^{n}x_i}{n}), where (n = 20). So (\bar{x}=\frac{83714}{20}=4185.7)
Step3: Calculate the squared - differences ((x_i-\bar{x})^2)
For example, when (x_1 = 4444), ((x_1-\bar{x})^2=(4444 - 4185.7)^2=(258.3)^2 = 66718.89). Do this for all (i) from (1) to (20) and sum them up. Let (Q=\sum_{i = 1}^{20}(x_i - \bar{x})^2). (Q=(4444 - 4185.7)^2+(4085 - 4185.7)^2+(4078 - 4185.7)^2+(4444 - 4185.7)^2+(4001 - 4185.7)^2+(4322 - 4185.7)^2+(4345 - 4185.7)^2+(4398 - 4185.7)^2+(4175 - 4185.7)^2+(4319 - 4185.7)^2+(4211 - 4185.7)^2+(4239 - 4185.7)^2+(4133 - 4185.7)^2+(3922 - 4185.7)^2+(4494 - 4185.7)^2+(4172 - 4185.7)^2+(4263 - 4185.7)^2+(3911 - 4185.7)^2+(3935 - 4185.7)^2+(3976 - 4185.7)^2) (Q = 340740.2)
Step4: Calculate the variance (s^2)
The formula for the sample variance is (s^2=\frac{\sum_{i = 1}^{n}(x_i-\bar{x})^2}{n - 1}), with (n = 20). So (s^2=\frac{340740.2}{19}\approx17933.7)
Step5: Calculate the standard deviation (s)
The standard deviation (s=\sqrt{s^2}), so (s=\sqrt{17933.7}\approx133.9)
Answer:
Mean: (4185.7), Standard - deviation: (133.9)