members of a junior high basketball team want to brag about how tall they are. first, they measured each…

members of a junior high basketball team want to brag about how tall they are. first, they measured each players height in inches. now they have to decide whether the mean or the median is better. which measure of center should the team use? basketball teams height (in inches): 64, 67, 83, 65, 66, 62, 69. the teams mean height is . the teams median height is . if the team members want to brag about how tall they are, they should use their mean, median, outlier, tallest height.

members of a junior high basketball team want to brag about how tall they are. first, they measured each players height in inches. now they have to decide whether the mean or the median is better. which measure of center should the team use? basketball teams height (in inches): 64, 67, 83, 65, 66, 62, 69. the teams mean height is . the teams median height is . if the team members want to brag about how tall they are, they should use their mean, median, outlier, tallest height.

Answer

Explanation:

Step1: Calculate the mean

The formula for the mean $\bar{x}=\frac{\sum_{i = 1}^{n}x_{i}}{n}$, where $x_{i}$ are the data - points and $n$ is the number of data - points. Here, $n = 8$, and the data points are $64,67,83,65,66,62,69$. $\bar{x}=\frac{64 + 67+83+65+66+62+69}{8}=\frac{476}{8}=59.5$.

Step2: Arrange data for median

First, arrange the data in ascending order: $62,64,65,66,67,69,83$. Since $n = 8$ (an even number), the median is the average of the $\frac{n}{2}$th and $(\frac{n}{2}+1)$th ordered data - points. $\frac{n}{2}=4$ and $\frac{n}{2}+1 = 5$. The 4th value is $66$ and the 5th value is $67$. Median $=\frac{66 + 67}{2}=66.5$.

Step3: Analyze for bragging

The mean is affected by the outlier $83$. The median is a better measure of the "typical" height when there is an outlier. So, if the team members want to brag about how tall they are, they should use the median.

Answer:

Median