a meteorologist is studying the monthly rainfall in a section of the brazilian rainforest. she recorded the…

a meteorologist is studying the monthly rainfall in a section of the brazilian rainforest. she recorded the monthly rainfall, in inches, for last year. they were: 1.8, 2.5, 2.6, 4.4, 4.4, 7.3, 8.0, 9.5, 10.3, 10.4, 11.1, 11.7 for this data set: $mu = 7$, $n = 12$ $sigma^{2}=\frac{(x_{1}-mu)^{2}+(x_{2}-mu)^{2}+cdots+(x_{n}-mu)^{2}}{n}$ $sigma^{2}=\frac{(1.8 - 7)^{2}+(2.5 - 7)^{2}+cdots+(11.7 - 7)^{2}}{12}$ fill in the missing values in the formula. what is the variance? 0 3.217 3.522 12.405 148.86 done

a meteorologist is studying the monthly rainfall in a section of the brazilian rainforest. she recorded the monthly rainfall, in inches, for last year. they were: 1.8, 2.5, 2.6, 4.4, 4.4, 7.3, 8.0, 9.5, 10.3, 10.4, 11.1, 11.7 for this data set: $mu = 7$, $n = 12$ $sigma^{2}=\frac{(x_{1}-mu)^{2}+(x_{2}-mu)^{2}+cdots+(x_{n}-mu)^{2}}{n}$ $sigma^{2}=\frac{(1.8 - 7)^{2}+(2.5 - 7)^{2}+cdots+(11.7 - 7)^{2}}{12}$ fill in the missing values in the formula. what is the variance? 0 3.217 3.522 12.405 148.86 done

Answer

Explanation:

Step1: Calculate the squared - differences

$(1.8 - 7)^2=( - 5.2)^2 = 27.04$ $(2.5 - 7)^2=( - 4.5)^2 = 20.25$ $(2.6 - 7)^2=( - 4.4)^2 = 19.36$ $(4.4 - 7)^2=( - 2.6)^2 = 6.76$ $(4.4 - 7)^2=( - 2.6)^2 = 6.76$ $(7.3 - 7)^2=(0.3)^2 = 0.09$ $(8.0 - 7)^2=(1)^2 = 1$ $(9.5 - 7)^2=(2.5)^2 = 6.25$ $(10.3 - 7)^2=(3.3)^2 = 10.89$ $(10.4 - 7)^2=(3.4)^2 = 11.56$ $(11.1 - 7)^2=(4.1)^2 = 16.81$ $(11.7 - 7)^2=(4.7)^2 = 22.09$

Step2: Sum up the squared - differences

$27.04+20.25 + 19.36+6.76+6.76+0.09+1+6.25+10.89+11.56+16.81+22.09 = 148.86$

Step3: Divide by the number of data points

$\sigma^{2}=\frac{148.86}{12}=12.405$

Answer:

$12.405$