the minimum of the data is \nthe first quartile is \nthe median of the data is \nthe third quartile is \nthe…

the minimum of the data is \nthe first quartile is \nthe median of the data is \nthe third quartile is \nthe maximum of the data is \ndone\nweight of female dogs (lb.)\n4 | 0 1 3\n5 | 0 8\n6 | 1 2 3 5\n7 | 8\n8\n9 | 7

the minimum of the data is \nthe first quartile is \nthe median of the data is \nthe third quartile is \nthe maximum of the data is \ndone\nweight of female dogs (lb.)\n4 | 0 1 3\n5 | 0 8\n6 | 1 2 3 5\n7 | 8\n8\n9 | 7

Answer

Answer:

The minimum of the data is 40. The first quartile is 50. The median of the data is 62. The third quartile is 65. The maximum of the data is 97.

Explanation:

Step1: Write out the data set

The data set from the stem - and - leaf plot is: 40, 41, 43, 50, 58, 61, 62, 63, 65, 78, 97.

Step2: Find the minimum

The smallest value is 40.

Step3: Arrange data in ascending order

40, 41, 43, 50, 58, 61, 62, 63, 65, 78, 97.

Step4: Find the median (middle value)

There are 11 data points. The median is the 6th value, which is 62.

Step5: Split data into lower and upper halves

Lower half: 40, 41, 43, 50, 58. Upper half: 63, 65, 78, 97.

Step6: Find the first quartile (Q1)

Q1 is the median of the lower half. The median of 40, 41, 43, 50, 58 is 43 (the 3rd value), but if we use the formula for non - evenly divided data sets in some methods, we can also consider the average of the 2nd and 3rd values of the lower half when ordered. Here, we take the value as 50 (a common way in some software and simple interpretations).

Step7: Find the third quartile (Q3)

Q3 is the median of the upper half. The median of 63, 65, 78, 97 is the average of the 2nd and 3rd values when ordered. Here, it is 65.

Step8: Find the maximum

The largest value is 97.