the minimum of the data is \nthe first quartile is \nthe median of the data is \nthe third quartile is \nthe…
the minimum of the data is \nthe first quartile is \nthe median of the data is \nthe third quartile is \nthe maximum of the data is \ndone\nweight of female dogs (lb.)\n4 0 1 3\n5 0 8\n6 1 2 3 5\n7 8\n8\n9 7
Answer
Answer:
The minimum of the data is 40. The first quartile is 50. The median of the data is 61. The third quartile is 65. The maximum of the data is 97.
Explanation:
Step1: Write out data set
The data set from the stem - and - leaf plot is 40, 41, 43, 50, 58, 61, 62, 63, 65, 78, 97.
Step2: Find minimum
The smallest value in the set is 40.
Step3: Calculate first quartile
There are 11 data points. The position of the first quartile $Q_1$ is $\frac{n + 1}{4}=\frac{11+ 1}{4}=3$. The 3rd value in the ordered set is 50.
Step4: Find median
The position of the median for $n = 11$ is $\frac{n + 1}{2}=\frac{11+1}{2}=6$. The 6th value in the ordered set is 61.
Step5: Calculate third quartile
The position of the third quartile $Q_3$ is $\frac{3(n + 1)}{4}=\frac{3\times(11 + 1)}{4}=9$. The 9th value in the ordered set is 65.
Step6: Find maximum
The largest value in the set is 97.