a money envelope contains five $10 bills, ten $20 bills, and fifteen $50 bills. sandra randomly selects two…

a money envelope contains five $10 bills, ten $20 bills, and fifteen $50 bills. sandra randomly selects two bills without returning the first bill. what is the probability of getting a $10 bill then a $50 bill? write your answer in the simplest form of fraction. (1 point)

a money envelope contains five $10 bills, ten $20 bills, and fifteen $50 bills. sandra randomly selects two bills without returning the first bill. what is the probability of getting a $10 bill then a $50 bill? write your answer in the simplest form of fraction. (1 point)

Answer

Explanation:

Step1: Calculate total number of bills

The total number of bills is $5 + 10+15=30$.

Step2: Calculate probability of first - selecting a $10 bill

The probability of selecting a $10 bill first is $\frac{5}{30}=\frac{1}{6}$ since there are 5 $10 bills out of 30 total bills.

Step3: Calculate number of bills left after first selection

After selecting a $10 bill first, there are $30 - 1=29$ bills left.

Step4: Calculate probability of second - selecting a $50 bill

There are 15 $50 bills. So the probability of selecting a $50 bill second, given that a $10 bill was selected first, is $\frac{15}{29}$.

Step5: Calculate the combined probability

By the multiplication rule for dependent events, the probability of getting a $10 bill then a $50 bill is $\frac{1}{6}\times\frac{15}{29}=\frac{15}{174}=\frac{5}{58}$.

Answer:

$\frac{5}{58}$