at mountain high school, the students were surveyed about their participation in band (b) and track (t). the…

at mountain high school, the students were surveyed about their participation in band (b) and track (t). the results of the survey are shown in the venn diagram. given that a randomly chosen student participates in band, what is the probability that the student also participates in track?\no $\frac{9}{40}$\no $\frac{9}{33}$\no $\frac{24}{33}$\no $\frac{31}{40}$
Answer
Explanation:
Step1: Recall conditional - probability formula
The formula for conditional probability is $P(A|B)=\frac{P(A\cap B)}{P(B)}$. In the context of this problem, let $A$ be the event of participating in track and $B$ be the event of participating in band. Then $P(A|B)=\frac{n(A\cap B)}{n(B)}$, where $n(A\cap B)$ is the number of elements in the intersection of $A$ and $B$, and $n(B)$ is the number of elements in $B$.
Step2: Identify values from the Venn - diagram
From the Venn - diagram, the number of students who participate in both band and track $n(B\cap T)=9$, and the number of students who participate in band $n(B)=24 + 9=33$.
Step3: Calculate the conditional probability
Using the formula $P(T|B)=\frac{n(B\cap T)}{n(B)}$, we substitute $n(B\cap T) = 9$ and $n(B)=33$ to get $P(T|B)=\frac{9}{33}$.
Answer:
$\frac{9}{33}$