the movement of the progress bar may be uneven because questions can be worth more or less (including zero)…

Explanation:

Step1: Find the minimum value

The minimum value of the data - set (6,9,13,13,18,22,22,25,26,28,30,30) is (6).

Step2: Find the first - quartile ((Q_1))

The data set has (n = 12) values. The lower half of the data is (6,9,13,13,18,22). The median of the lower half ((Q_1)) is the average of the 3rd and 4th ordered values. (\frac{13 + 13}{2}=13).

Step3: Find the median ((Q_2))

Since (n = 12), the median is the average of the 6th and 7th ordered values. (\frac{22+22}{2}=22).

Step4: Find the third - quartile ((Q_3))

The upper half of the data is (22,25,26,28,30,30). The median of the upper half ((Q_3)) is the average of the 3rd and 4th ordered values of the upper - half. (\frac{26 + 28}{2}=27).

Step5: Find the maximum value

The maximum value of the data set is (30).

A box - and - whisker plot has a box from (Q_1) to (Q_3) with a line at the median ((Q_2)), and whiskers from the minimum to (Q_1) and from (Q_3) to the maximum.

Answer:

We need to check which box - and - whisker plot has a minimum of (6), (Q_1 = 13), median (=22), (Q_3 = 27), and maximum of (30). Without the actual visual selection of the correct plot among the given options, we have calculated the key values for constructing the box - and - whisker plot. If you were to select from the given plots, you would look for a plot where the left - most point (whisker end) is at (6), the left side of the box is at (13), the line inside the box is at (22), the right side of the box is at (27), and the right - most point (whisker end) is at (30).