movie critics claim that 68% of adults and 79% of teenagers would recommend seeing the newest action movie…

movie critics claim that 68% of adults and 79% of teenagers would recommend seeing the newest action movie. suppose random samples of 43 adults and 52 teenagers are selected. let $hat{p}_a$ and $hat{p}_t$ be the sample proportions of adult and teenage moviegoers, respectively, who would recommend this movie. which of the following is the mean of the sampling distribution of $hat{p}_a - hat{p}_t$? -0.11 0.11 0.74 1.47
Answer
Answer:
-0.11
Explanation:
Step1: Recall the formula for mean of difference of sample proportions
$\mu_{\hat{p}_A-\hat{p}_T}=p_A - p_T$
Step2: Identify population - proportions
$p_A = 0.68$, $p_T=0.79$
Step3: Calculate the mean
$\mu_{\hat{p}_A-\hat{p}_T}=0.68 - 0.79=-0.11$