mr. walker is looking at the fundraiser totals for the last five years. how does the mean of the totals…

mr. walker is looking at the fundraiser totals for the last five years. how does the mean of the totals compare to the median? yearly fundraiser totals\n| year | total |\n| ---- | ---- |\n| 1 | $896 |\n| 2 | $925 |\n| 3 | $880 |\n| 4 | $963 |\n| 5 | $914 | the median is $1.60 greater than the mean. the mean is $1.60 greater than the median. the median is $2.82 greater than the mean. the mean is $2.82 greater than the median.

mr. walker is looking at the fundraiser totals for the last five years. how does the mean of the totals compare to the median? yearly fundraiser totals\n| year | total |\n| ---- | ---- |\n| 1 | $896 |\n| 2 | $925 |\n| 3 | $880 |\n| 4 | $963 |\n| 5 | $914 | the median is $1.60 greater than the mean. the mean is $1.60 greater than the median. the median is $2.82 greater than the mean. the mean is $2.82 greater than the median.

Answer

Explanation:

Step1: Calculate the mean

The mean $\bar{x}=\frac{896 + 925+880+963+914}{5}=\frac{4578}{5}=915.6$.

Step2: Arrange data in ascending - order

The data in ascending - order is $880,896,914,925,963$.

Step3: Calculate the median

Since $n = 5$ (odd), the median is the middle - value. So the median is $914$.

Step4: Find the difference

The difference between the mean and the median is $915.6−914 = 1.6$. So the mean is $$1.60$ greater than the median.

Answer:

The mean is $1.60 greater than the median.