mr. walker is looking at the fundraiser totals for the last five years.\nhow does the mean of the totals…

mr. walker is looking at the fundraiser totals for the last five years.\nhow does the mean of the totals compare to the median?\nyearly fundraiser totals\n| year | total |\n| ---- | ---- |\n| 1 | $896 |\n| 2 | $925 |\n| 3 | $880 |\n| 4 | $963 |\n| 5 | $914 |\nthe median is $1.60 greater than the mean.\nthe mean is $1.60 greater than the median.\nthe median is $2.82 greater than the mean.\nthe mean is $2.82 greater than the median.

mr. walker is looking at the fundraiser totals for the last five years.\nhow does the mean of the totals compare to the median?\nyearly fundraiser totals\n| year | total |\n| ---- | ---- |\n| 1 | $896 |\n| 2 | $925 |\n| 3 | $880 |\n| 4 | $963 |\n| 5 | $914 |\nthe median is $1.60 greater than the mean.\nthe mean is $1.60 greater than the median.\nthe median is $2.82 greater than the mean.\nthe mean is $2.82 greater than the median.

Answer

Explanation:

Step1: Calculate the mean

First, sum the totals: $896 + 925+880 + 963+914=4578$. Then divide by the number of years ($n = 5$). Mean=$\frac{4578}{5}=915.6$.

Step2: Calculate the median

Arrange the totals in ascending - order: $880,896,914,925,963$. The middle value (since $n = 5$, the third - value) is the median, so the median is $914$.

Step3: Find the difference

Subtract the median from the mean: $915.6−914 = 1.6$.

Answer:

The mean is $1.60$ greater than the median.