mr. walker is looking at the fundraiser totals for the last five years. how does the mean of the totals…

mr. walker is looking at the fundraiser totals for the last five years. how does the mean of the totals compare to the median? yearly fundraiser totals\n| year | total |\n| ---- | ---- |\n| 1 | $896 |\n| 2 | $925 |\n| 3 | $880 |\n| 4 | $963 |\n| 5 | $914 |\nthe median is $1.60 greater than the mean.\nthe mean is $1.60 greater than the median.\nthe median is $2.82 greater than the mean.\nthe mean is $2.82 greater than the median.

mr. walker is looking at the fundraiser totals for the last five years. how does the mean of the totals compare to the median? yearly fundraiser totals\n| year | total |\n| ---- | ---- |\n| 1 | $896 |\n| 2 | $925 |\n| 3 | $880 |\n| 4 | $963 |\n| 5 | $914 |\nthe median is $1.60 greater than the mean.\nthe mean is $1.60 greater than the median.\nthe median is $2.82 greater than the mean.\nthe mean is $2.82 greater than the median.

Answer

Answer:

The mean is $1.60$ greater than the median.

Explanation:

Step1: Calculate the mean

$\text{Mean}=\frac{896 + 925+880+963+914}{5}=\frac{4578}{5}=915.6$

Step2: Arrange data in ascending - order

$880,896,914,925,963$

Step3: Find the median

Since $n = 5$ (odd), the median is the middle - value. So, the median is $914$.

Step4: Compare mean and median

$915.6-914 = 1.6$ The mean is $1.60$ greater than the median.