mr. walker is looking at the fundraiser totals for the last five years. how does the mean of the totals…

mr. walker is looking at the fundraiser totals for the last five years. how does the mean of the totals compare to the median? yearly fundraiser totals\n| year | total |\n| ---- | ---- |\n| 1 | $896 |\n| 2 | $925 |\n| 3 | $880 |\n| 4 | $963 |\n| 5 | $914 |

mr. walker is looking at the fundraiser totals for the last five years. how does the mean of the totals compare to the median? yearly fundraiser totals\n| year | total |\n| ---- | ---- |\n| 1 | $896 |\n| 2 | $925 |\n| 3 | $880 |\n| 4 | $963 |\n| 5 | $914 |

Answer

Explanation:

Step1: Calculate the mean

The mean $\bar{x}=\frac{896 + 925+880+963+914}{5}=\frac{4578}{5}=915.6$

Step2: Arrange data in ascending - order

$880,896,914,925,963$. The median is the middle - value. Since $n = 5$ (odd), the median $M = 914$.

Step3: Find the difference

$915.6-914 = 1.6$

Answer:

The mean is $1.60 greater than the median.