mr. walker is looking at the fundraiser totals for the last five years.\n\nyearly fundraiser totals\n| year…

mr. walker is looking at the fundraiser totals for the last five years.\n\nyearly fundraiser totals\n| year | total |\n| ---- | ---- |\n| 1 | $896 |\n| 2 | $925 |\n| 3 | $880 |\n| 4 | $963 |\n| 5 | $914 |\n\nhow does the mean of the totals compare to the median?\nthe median is $1.60 greater than the mean.\nthe mean is $1.60 greater than the median.\nthe median is $2.82 greater than the mean.\nthe mean is $2.82 greater than the median.

mr. walker is looking at the fundraiser totals for the last five years.\n\nyearly fundraiser totals\n| year | total |\n| ---- | ---- |\n| 1 | $896 |\n| 2 | $925 |\n| 3 | $880 |\n| 4 | $963 |\n| 5 | $914 |\n\nhow does the mean of the totals compare to the median?\nthe median is $1.60 greater than the mean.\nthe mean is $1.60 greater than the median.\nthe median is $2.82 greater than the mean.\nthe mean is $2.82 greater than the median.

Answer

Explanation:

Step1: Calculate the mean

Sum of totals: $896 + 925+880 + 963+914=4578$. Mean = $\frac{4578}{5}=915.6$.

Step2: Arrange data in ascending - order

$880,896,914,925,963$. Median is the middle - value, so median = $914$.

Step3: Find the difference

Difference between mean and median: $915.6−914 = 1.6$. So the mean is $$1.60$ greater than the median.

Answer:

The mean is $1.60$ greater than the median.