mr. walker is looking at the fundraiser totals for the last five years. yearly fundraiser totals\n| year |…

mr. walker is looking at the fundraiser totals for the last five years. yearly fundraiser totals\n| year | total |\n| ---- | ---- |\n| 1 | $896 |\n| 2 | $925 |\n| 3 | $880 |\n| 4 | $963 |\n| 5 | $914 |\nhow does the mean of the totals compare to the median?\nthe mean is $1.60 greater than the median.\nthe mean is $2.82 greater than the median.\nthe median is $1.60 greater than the mean.\nthe median is $2.82 greater than the mean.

mr. walker is looking at the fundraiser totals for the last five years. yearly fundraiser totals\n| year | total |\n| ---- | ---- |\n| 1 | $896 |\n| 2 | $925 |\n| 3 | $880 |\n| 4 | $963 |\n| 5 | $914 |\nhow does the mean of the totals compare to the median?\nthe mean is $1.60 greater than the median.\nthe mean is $2.82 greater than the median.\nthe median is $1.60 greater than the mean.\nthe median is $2.82 greater than the mean.

Answer

Explanation:

Step1: Calculate the mean

The mean $\bar{x}=\frac{896 + 925+880 + 963+914}{5}=\frac{4578}{5}=915.6$

Step2: Arrange data in ascending - order

$880,896,914,925,963$. Since $n = 5$ (odd), the median is the middle - value. So the median $=914$

Step3: Find the difference

The difference between the mean and the median is $915.6−914 = 1.6$

Answer:

The mean is $1.60 greater than the median.