multiple answer 10 points. the running times for the 100 are posted by the ohs track team is approximately…

multiple answer 10 points. the running times for the 100 are posted by the ohs track team is approximately normal with a mean time 13.4 seconds with a standard deviation of 1.6 sec. select the most appropriate answer(s) for a player who ran an 8.6. the time is about average relative to other runners. the players time is too far to the right. the players time is in the 3 sd to the left. the players time is an anomaly. the time is not even in the distribution.

multiple answer 10 points. the running times for the 100 are posted by the ohs track team is approximately normal with a mean time 13.4 seconds with a standard deviation of 1.6 sec. select the most appropriate answer(s) for a player who ran an 8.6. the time is about average relative to other runners. the players time is too far to the right. the players time is in the 3 sd to the left. the players time is an anomaly. the time is not even in the distribution.

Answer

Explanation:

Step1: Calculate z - score

The z - score formula is $z=\frac{x-\mu}{\sigma}$, where $x = 8.6$, $\mu=13.4$, and $\sigma = 1.6$. So $z=\frac{8.6 - 13.4}{1.6}=\frac{-4.8}{1.6}=-3$.

Step2: Analyze z - score in normal distribution

In a normal distribution, about 99.7% of the data lies within 3 standard - deviations of the mean ($z$ values between - 3 and 3). A $z$ - score of - 3 means the value is 3 standard deviations to the left of the mean. Values that are more than 3 standard deviations from the mean are considered anomalies.

Answer:

The player's time is in the 3 SD to the left The player's time is an anomaly