multiple choice 1 point\nthe average height for the players on a high school basketball team is 72 inches…

multiple choice 1 point\nthe average height for the players on a high school basketball team is 72 inches with a standard deviation of zero. interpret this information\nthere are no players that are 72 inches tall.\nevery player on the team is 72 inches tall.\nhalf the team is taller than 72 inches and half the team is shorter than 72 inches.\nfill in the blank 1 point\nsample annual salaries (in thousands of dollars) for employees at a company are listed.\n50 54 55 64 39 39 50 54 55 25 64 50 53\nthe sample standard deviation is s = type your answer. thousand dollars. round to 1 decimal place.

multiple choice 1 point\nthe average height for the players on a high school basketball team is 72 inches with a standard deviation of zero. interpret this information\nthere are no players that are 72 inches tall.\nevery player on the team is 72 inches tall.\nhalf the team is taller than 72 inches and half the team is shorter than 72 inches.\nfill in the blank 1 point\nsample annual salaries (in thousands of dollars) for employees at a company are listed.\n50 54 55 64 39 39 50 54 55 25 64 50 53\nthe sample standard deviation is s = type your answer. thousand dollars. round to 1 decimal place.

Answer

5.

Brief Explanations:

The standard - deviation measures the amount of variation or dispersion of a set of values. A standard deviation of zero means there is no variation. So, if the average height of players on a high - school basketball team is 72 inches with a standard deviation of zero, every player's height is equal to the mean height, which is 72 inches.

Answer:

B. Every player on the team is 72 inches tall.

6.

Explanation:

Step1: Calculate the mean

The data set is (x = {50,54,55,64,39,39,50,54,55,25,64,50,53}). The number of data points (n = 13). The mean (\bar{x}=\frac{\sum_{i = 1}^{n}x_{i}}{n}=\frac{50 + 54+55+64+39+39+50+54+55+25+64+50+53}{13}=\frac{658}{13}\approx50.6)

Step2: Calculate the squared differences

((x_1-\bar{x})^2=(50 - 50.6)^2=0.36), ((x_2 - 50.6)^2=(54 - 50.6)^2 = 11.56), ((x_3-50.6)^2=(55 - 50.6)^2 = 19.36), ((x_4-50.6)^2=(64 - 50.6)^2=179.56), ((x_5-50.6)^2=(39 - 50.6)^2 = 134.56), ((x_6-50.6)^2=(39 - 50.6)^2 = 134.56), ((x_7-50.6)^2=(50 - 50.6)^2=0.36), ((x_8-50.6)^2=(54 - 50.6)^2 = 11.56), ((x_9-50.6)^2=(55 - 50.6)^2 = 19.36), ((x_{10}-50.6)^2=(25 - 50.6)^2 = 655.36), ((x_{11}-50.6)^2=(64 - 50.6)^2=179.56), ((x_{12}-50.6)^2=(50 - 50.6)^2=0.36), ((x_{13}-50.6)^2=(53 - 50.6)^2 = 5.76)

Step3: Calculate the sum of squared differences

(\sum_{i = 1}^{n}(x_{i}-\bar{x})^2=0.36+11.56+19.36+179.56+134.56+134.56+0.36+11.56+19.36+655.36+179.56+0.36+5.76 = 1352.4)

Step4: Calculate the sample standard deviation

The formula for the sample standard deviation (s=\sqrt{\frac{\sum_{i = 1}^{n}(x_{i}-\bar{x})^2}{n - 1}}) (s=\sqrt{\frac{1352.4}{13 - 1}}=\sqrt{\frac{1352.4}{12}}=\sqrt{112.7}=10.6)

Answer:

10.6