e and f are mutually exclusive events. p(e) = 0.1; p(f) = 0.6. find p(e | f)
e and f are mutually exclusive events. p(e) = 0.1; p(f) = 0.6. find p(e | f)
Answer
Explanation:
Step1: Recall conditional - probability formula
The formula for conditional probability is $P(E|F)=\frac{P(E\cap F)}{P(F)}$.
Step2: Use the property of mutually - exclusive events
Since $E$ and $F$ are mutually exclusive events, $P(E\cap F) = 0$.
Step3: Calculate $P(E|F)$
Substitute $P(E\cap F)=0$ and $P(F) = 0.6$ into the conditional - probability formula: $P(E|F)=\frac{0}{0.6}=0$.
Answer:
$0$