nine wolves, eight female and one male, are to be released into the wild three at a time. if the male wolf…

nine wolves, eight female and one male, are to be released into the wild three at a time. if the male wolf is to be in the first released group and order does not matter, in how many ways can the first group of three wolves be formed?\n28 ways\n36 ways\n56 ways\n84 ways

nine wolves, eight female and one male, are to be released into the wild three at a time. if the male wolf is to be in the first released group and order does not matter, in how many ways can the first group of three wolves be formed?\n28 ways\n36 ways\n56 ways\n84 ways

Answer

Explanation:

Step1: Determine remaining wolves to choose from

Since the male wolf is in the first - group, we need to choose 2 more wolves from 8 female wolves.

Step2: Use combination formula

The combination formula is $C(n,k)=\frac{n!}{k!(n - k)!}$, where $n = 8$ (number of female wolves) and $k=2$ (number of wolves to choose). $C(8,2)=\frac{8!}{2!(8 - 2)!}=\frac{8!}{2!×6!}=\frac{8\times7\times6!}{2\times1\times6!}=28$

Answer:

28 ways