nine wolves, eight female and one male, are to be released into the wild three at a time. if the male wolf…

nine wolves, eight female and one male, are to be released into the wild three at a time. if the male wolf is to be in the first released group and order does not matter, in how many ways can the first group of three wolves be formed?\no 28 ways\no 36 ways\no 56 ways\no 84 ways

nine wolves, eight female and one male, are to be released into the wild three at a time. if the male wolf is to be in the first released group and order does not matter, in how many ways can the first group of three wolves be formed?\no 28 ways\no 36 ways\no 56 ways\no 84 ways

Answer

Explanation:

Step1: Determine the remaining number of wolves to choose

Since the male wolf is already in the group, we need to choose 2 more wolves from the 8 female wolves.

Step2: Use the combination formula

The combination formula is $C(n,k)=\frac{n!}{k!(n - k)!}$, where $n = 8$ (number of female wolves) and $k=2$ (number of wolves to choose from the females). $C(8,2)=\frac{8!}{2!(8 - 2)!}=\frac{8!}{2!×6!}=\frac{8\times7}{2\times1}=28$

Answer:

28 ways